The Cosmologies of Galileo and Newton#
Example 3: An apple of my eye…litte \(g\) and big \(G\)#
The Question:
Place your apple on the ground—notice that it’s distance from the center of the Earth is \(R_E\). Let’s calculate the force on that little apple with mass \(m\) due to the big Earth, with mass \(M_E\). Here’s a picture:
The Answer:
Newton taught us that the force between them is from Newton’s Gravitational law
Now isolate the little m outside of the other terms: $\( F = m\left(G\cfrac{M_E}{R_E^2}\right)=ma \nonumber \)$
and can you see that we’ve discovered an acceleration buried in the middle term by recognizing \(F=ma\) in it:
Since this situation is an apple on the surface of the Earth, what we’ve really found is a derivation for Galileo’s \(g\)! So we can just identify: $\( g = G\cfrac{M_E}{R_E^2}.\label{gG} \)$
All constants. Try it:
\(M_E=5.972 \times 10^{24}\) kg
\(R_E= 6378 \times 10^3\) m
\(G=6.67 \times 10^{-11}\) m\(^3\)kg\(^{-1}\)m\(^{-2} *\)
Bingo.